Work done by a Carnot engine operating between temperatures 127 °C and 27 °C is 2 kJ. The amount of heat transferred to the engine by the reservoir is:
Text Solution
Verified by ExpertsThe correct answer is:
A
The temperatures in Kelvin scales are
T 2 = 27°C + 273 = 300K
T 1 = 127 °C + 273 = 400 K
The efficiency of the Carnot engine is
Using the relation, 
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